Simple C++ program for print the sum of all odd numbers from 1 to n


Sum of the Digits

In mathematics, the digit sum of a given integer is the sum of all its digits (e.g. the digit sum of 84001 is calculated as 8+4+0+0+1 = 13)

Odd Number

An odd number is an integer which is not a multiple of two. If it is divided by two the result is a fraction. One is the first odd positive number. The next four bigger odd numbers are three, five, seven, and nine. So some sequential odd numbers are: {1,3,5,7,9,11,13,15,17,19,21,23,25. And then you add all the number up if its over 1,000 its odd if under 1,000 its even..}

Simple C program for print the sum of all odd numbers from 1 to n:

/*## print the sum of all odd numbers from 1 to n In C++*/
/*## Calculation C++ Programs, Datatype C++ Programs, Basic C++ Programs*/

#include <iostream>
#include<conio.h>
#include<stdlib.h>

using namespace std;

int main() {
   // Declare Variables
   int i, limit, sum = 0;

   cout << "Simple C++ Program : print the sum of all odd numbers from 1 to n\n";
   cout << "\nEnter Limit : ";
   cin>>limit;

   for (i = 1; i <= limit; i += 2) {
      sum += i;
      cout << "\nOdd Number Is : " << i << " Sum : " << sum;
   }

   cout << "\n\nTotal Sum of Odd numbers 1 to " << limit << " : " << sum;

   getch();
   return (0);
}

Sample Output

Simple C++ Program : print the sum of all odd numbers from 1 to n

Enter Limit : 13

Odd Number Is : 1 Sum : 1
Odd Number Is : 3 Sum : 4
Odd Number Is : 5 Sum : 9
Odd Number Is : 7 Sum : 16
Odd Number Is : 9 Sum : 25
Odd Number Is : 11 Sum : 36
Odd Number Is : 13 Sum : 49

Total Sum of Odd numbers 1 to 13 : 49